1.题目要求根据一定的分数范围，对学生进行排序输出。
2.题目提到各个同学的分数是唯一的，所以可以采用分数作为下标，直接建立101个学生节点，即0~100分。
3.然后根据最高分限制和最低分限制，筛选出学生进行输出。
Given a list of N student records with name, ID and grade. You are supposed to sort the records with respect to the grade in non-increasing order, and output those student records of which the grades are in a given interval.
Input Specification:
Each input file contains one test case. Each case is given in the following format:
N name[1] ID[1] grade[1] name[2] ID[2] grade[2] ... ... name[N] ID[N] grade[N] grade1 grade2
where name[i] and ID[i] are strings of no more than 10 characters with no space, grade[i] is an integer in [0, 100], grade1 and grade2 are the boundaries of the grade’s interval. It is guaranteed that all the grades are distinct.
Output Specification:
For each test case you should output the student records of which the grades are in the given interval [grade1, grade2] and are in non-increasing order. Each student record occupies a line with the student’s name and ID, separated by one space. If there is no student’s grade in that interval, output “NONE” instead.
Sample Input 1:
4 Tom CS000001 59 Joe Math990112 89 Mike CS991301 100 Mary EE990830 95 60 100
Sample Output 1:
Mike CS991301 Mary EE990830 Joe Math990112
Sample Input 2:
2 Jean AA980920 60 Ann CS01 80 90 95
Sample Output 2:
NONE
AC代码：
//#include<string>
//#include <iomanip>
//#include<stack>
//#include<unordered_set>
//#include <sstream>
//#include "func.h"
//#include <list>
#include<unordered_map>
#include<set>
#include<queue>
#include<map>
#include<vector>
#include <algorithm>
#include<stdio.h>
#include<iostream>
#include<string>
#include<memory.h>
#include<limits.h>
#include<stack>
using namespace std;
struct StudentNode{
string id, name;
StudentNode() :id(""), name(""){};
};
int main(void)
{
vector<StudentNode> student(101);
int n;
cin >> n;
for (int i = 0; i < n; i++)
{
int grade;
string name, id;
cin >> name >> id >> grade;
student[grade].name = name;
student[grade].id = id;
}
int minGrade , maxGrade;
cin >> minGrade >> maxGrade;
vector<StudentNode> ans(0);
for (int i = maxGrade; i >= minGrade; i--)
{
if (student[i].name!="")
{
ans.push_back(student[i]);
}
}
if (ans.size() == 0)
cout << "NONE" << endl;
else
{
for (int i = 0; i < ans.size(); i++)
cout << ans[i].name << " " << ans[i].id << endl;
}
return 0;
}