1.这道题目主要是求家族树中，哪一层的成员数最多，输出成员数和该层层数。
2.主要考察了层次遍历和数据结构的设计。
A family hierarchy is usually presented by a pedigree tree where all the nodes on the same level belong to the same generation. Your task is to find the generation with the largest population.
Input Specification:
Each input file contains one test case. Each case starts with two positive integers N (<100) which is the total number of family members in the tree (and hence assume that all the members are numbered from 01 to N), and M (<N) which is the number of family members who have children. Then M lines follow, each contains the information of a family member in the following format:
ID K ID[1] ID[2] … ID[K]
where ID is a two-digit number representing a family member, K (>0) is the number of his/her children, followed by a sequence of two-digit ID’s of his/her children. For the sake of simplicity, let us fix the root ID to be 01. All the numbers in a line are separated by a space.
Output Specification:
For each test case, print in one line the largest population number and the level of the corresponding generation. It is assumed that such a generation is unique, and the root level is defined to be 1.
Sample Input:
23 13 21 1 23 01 4 03 02 04 05 03 3 06 07 08 06 2 12 13 13 1 21 08 2 15 16 02 2 09 10 11 2 19 20 17 1 22 05 1 11 07 1 14 09 1 17 10 1 18
Sample Output:
9 4
AC代码：
//#include<string>
//#include <iomanip>
#include<vector>
#include <algorithm>
//#include<stack>
#include<set>
#include<queue>
#include<map>
//#include<unordered_set>
#include<unordered_map>
//#include <sstream>
//#include "func.h"
//#include <list>
#include<stdio.h>
#include<iostream>
#include<string>
#include<memory.h>
#include<limits.h>
using namespace std;
struct Node{
vector<int> list;
Node() :list(0){};
};
int main(void)
{
int totalNum, recordNum;
cin >> totalNum >> recordNum;
vector<Node> tree(totalNum+1);
for (int i = 0; i < recordNum; i++)
{
int id, n;
cin >> id >> n;
for (int j = 0; j < n; j++)
{
int tmp;
cin >> tmp;
tree[id].list.push_back(tmp);
}
}
queue<int> q;
q.push(1);
int count1 = 1;
int count2 = 0;
int maxFamilyMember = 1, maxFamilyLevel = 1;
int level = 1;
while (!q.empty())
{
for (int i = 0; i < count1; i++)
{
int root = q.front(); q.pop();
for (int j = 0; j < tree[root].list.size(); j++)
{
q.push(tree[root].list[j]);
}
count2 += tree[root].list.size();
}
level++;
if (count2 > maxFamilyMember)
{
maxFamilyMember = count2;
maxFamilyLevel = level;
}
count1 = count2;
count2 = 0;
}
cout << maxFamilyMember << " " << maxFamilyLevel << endl;
return 0;
}